the answer to this is D because the equation is neither divisible by 2a+1 nor a+1
2007-06-04 02:49:59
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answer #1
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answered by Anonymous
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D) Neither A nor B.
After factoring out the 6, you have 2a^2 + 3a + 2. The discriminant (the expression under the radical in the quadratic equation) is 3^2 - 4(2)(2) = 9 - 16 = -7. Since -7 is under the radical, the two roots are complex conjugates. Therefore a+1 and 2a+1 cannot be factors; they would lead to real roots.
2007-06-04 02:49:48
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answer #2
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answered by TFV 5
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one factor of 12a^2 + 18a + 12 = 0 is 6 (obviously)
divide by 6 we get
2a^2 + 3a + 2 - which factors into (2a+1)(a+1) + 1
So neither A nor B are factors
2007-06-04 03:01:36
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answer #3
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answered by welcome news 6
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D) Neither.
If you factor a 6 out of
12a^2 + 18a + 12 you get
6*(2a² + 3a + 2) and (2a² + 3a + 2) doesn't contain any of the factors listed.
Doug
2007-06-04 02:48:02
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answer #4
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answered by doug_donaghue 7
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D) Neither A nor B.
Synthetic division for 2a+1 and a+1 fails.
2007-06-04 02:47:12
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answer #5
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answered by Anonymous
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D) Neither, you can't factor an a out because the 12 has no a
2007-06-04 02:59:01
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answer #6
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answered by Adam A 2
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An employer interviews people for technical support positions in a company, and of the people are men. If all are qualified, in how many ways can the employer fill the technical support positions if exactly is a man?
2016-05-21 00:22:07
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answer #7
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answered by nellie 3
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You know titles like that only make me more eager to avoid such questions.
2007-06-04 02:47:41
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answer #8
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answered by Anonymous
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I do not have time to answer but this is the quadratic equation.
2007-06-04 02:43:54
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answer #9
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answered by starsun moon 3
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if u dont know that then u r slow my 5 year cuz know that stay in school
2007-06-04 02:44:39
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answer #10
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answered by gangsta_girl_631 1
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