What weight of calcium contains the same number of atoms as are present in 3.2 gms of sulphur?
2007-06-04 01:47:46 · 6 answers · asked by genius 2 in Science & Mathematics ➔ Mathematics
I got 4.0 grams and think I'm on the right track
each mole of any element contains 6.022 x 10^23 number of atoms ( just like a dozen of anything in life =12)
so you need to find how many moles you have of sulpher, how many moles of sulpher you make equivilant to number of moles of calcium and then convert that to grams of calcium
32. grams sulphur = 1mole sulphur/32.07grams sulphur (weight taken from periodic table) = .1moles sulphur
therefore go by .1 moles calcium as well
.1 moles calcium = 40.08g calcium/1 mole = 4grams calcium (the 40.08 weight of calcium)
good luck
2007-06-04 01:58:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
4 gms.. the atomic weights of sulphur n calcium are 32 n 40 respectively... hence 4gms of calcium will contain the same amt of atoms as 3.2 gms of sulphur
2007-06-04 01:52:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Divide 3.2 by the atomic weight of sulpher (which I don't know off the top). That will be the number of moles of sulpher you have. Now multiply that by the atomic weight of calcium to get the number of grams in the equivalent number of moles of calcium. Since a mole (or gram-equivalent) of anything hasd one Avogadros number (6.02*10^23) atoms in it, that will be the amount of calcium required.
Doug
2007-06-04 01:54:35 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
The most common isotope of sulfur (S-16) has an atomic weight of 32.065 grams/mole and the most common isotope of calcium (Ca-20) has an atomic weight of 40.078 grams/mole. Since Calcium has a higher atomic weight than Sulfur, you would expect that a sample with the same number of the same number of it takes fewer atoms of calcium
To equate the number of atoms in the substances you equate their molarity.
So 3.2 grams of sulfur is 3.2/32.065=0.0998 moles thus we want to know how many grams of Calcium make 0.0998 moles and the answer is simply 40.078*0.0998 = 3.9998 grams.
2007-06-04 01:57:48 · answer #4 · answered by Astral Walker 7 · 0⤊ 1⤋
4 gm
2007-06-04 02:34:37 · answer #5 · answered by tarun g 1 · 0⤊ 0⤋
3.99751 g calcium contains same # of atoms as 3.2 grams of sulfur.
3.2g/32.1 = 0.09969 where 32.1 is amu for S
so, there are 0.09969 mol S. You want 0.09969 mol Ca
amu Ca= 40.1
(x)/40.1 = 0.09969 solve for x ; x=3.99751
2007-06-04 02:05:37 · answer #6 · answered by madscientist 3 · 0⤊ 0⤋