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2007-06-03 23:51:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
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2007-06-04 00:00:12 · answer #1 · answered by xprof 3 · 0⤊ 2⤋
Pure Gold Coin
2016-10-17 21:34:29 · answer #2 · answered by ? 4 · 0⤊ 0⤋
since the heat capacity of gold is 25.418 J/molK, and a mol weight of 197, u have 60.91mmol.
each mol needs 25.4 J to rise the temp with 1 degree. (at 25 degrees, have in mind).
so your 0.069 mol absorb a total of 89J, and dividing that through 25 will give u the temp change in K
2007-06-04 00:03:42 · answer #3 · answered by chem_freak 5 · 0⤊ 0⤋
Specific heat of gold is 0.128 Joules/gm/C and using that information and the formula,
Q = m.s.dT
89 = 12 x 0.128xdT
dT = 89 / (12 X 0.128) = 57.94 C
2007-06-04 00:00:53 · answer #4 · answered by Swamy 7 · 2⤊ 1⤋
q = cm(delta-T)
delta-T therefore equals q/(cm)
c for gold is 0.129 J/gK
The answer would therefore be (89J)/[(0.129J/gK)(12g)], which is 57 Kelvins (or 57 Celsius degrees).
2007-06-03 23:58:25 · answer #5 · answered by Skepticat 6 · 0⤊ 0⤋