solve for x
1. x(2x+1)-2(x+1)=2(X-1)
2. (x+2)(2x-1)=2x(x+3)
3. x^2-3=(2+x)(3+x)
Thanks!
2007-06-03 23:18:57 · 7 answers · asked by Jane 1 in Science & Mathematics ➔ Mathematics
1. x(2x + 1) - 2(x +1) = 2(x - 1)
2x^2 + x - 2x - 2 = 2x - 2
2x^2 - x - 2x = 0
2x^2 - 3x = 0
x(2x - 3) = 0
x = 0 or 2x - 3 = 0 => x = 3/2
2. (x+2)(2x-1)= 2x(x+3)
2x^2 + 4x - x - 2 = 2x^2 + 6x
3x - 6x = 2
-3x = 2
x = -2/3
3. x^2 - 3 = (2 +x )(3+x)
x^2 - 3 = 6 + 3x + 2x + x^2
3x + 2x = - 3 -6
5x = -9
x = -9/5
2007-06-04 03:55:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. x(2x + 1) - 2(x + 1) = 2(x - 1)
Expanding the terms, we get
2x^2 + x - 2x - 2 - 2x + 2 = 0
2x^2 -3x = 0
x (2x - 3) = 0
So, x = 0 and x = 3/2 are the two values
2. (x+2)(2x+1) = 2x(x+3)
2x^2 +x + 4x + 2 = 2X^2 + 6x
2x^2 - 2x^2 + 5x - 6x + 2 = 0
-x + 2 = 0 or x = 2
3. x^2 - 3 = 6 + 2x + 3x + x^2
x^2 - x^2 + 5x + 9 = 0
5x = - 9
x = -9/5
2007-06-04 06:54:18 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
1. x(2x+1)-2(x+1)=2(X-1)
2x^2 + x -2x -2 = 2x -2
2x^2 -x -2 -2x +2 = 0
2x^2 -3x -2 = 0
( 2x+1 )( x - 2 ) = 0
2x + 1 = 0 or x - 2 = 0
2x= -1 or x = 2
x = -1/2 or x = 2
2. (x+2)(2x-1)=2x(x+3)
2 x^2 -3x -2 = 2x^2 + 6x
2x^2 -3x - 2 -2x^2 -6x = 0
-9x -2 = 0
-9x = 2
x = -2/ 9
3. x^2-3=(2+x)(3+x)
x^2 -3 = 6 + 5x + x^2
x^2 - 3 - 6 - 5x -x^2 = 0
-5x -9 = 0
-5x = 9
x = -9/5
2007-06-04 06:30:32 · answer #3 · answered by muhamed a 4 · 0⤊ 0⤋
x(2x+1)-2(x+1) = 2(x-1)
x(2x+1)-2(x+1)-2(x-1) = 0
x(2x+1)-2(x+1+x-1) = 0
x(2x+1)-2(x+x) = 0
2x^2 + x - 2 * 2x = 0
2x^2 + x - 4x = 0
2x^2 - 3x = 0
x(2x-3) = 0
x = 0, 2x-3=0
x = 0, x = 3/2 = 1.5
(x+2)(2x-1) = 2x(x+3)
x * 2x + x * -1 + 2*2x + 2 * -1 = 2x^2 + 6x
2x^2-x+4x-2 - 2x^2-6x = 0
-x+4x-6x-2 = 0
-3x-2 = 0
-3x = 2
x = -2/3
x^2-3 = (2+x)(3+x)
x^2-3 - (2+x)(3+x) = 0
x^2-3 - (2*3+2*x+x*3+x*x) = 0
x^2-3 - (6 + 2x+3x+x^2) = 0
x^2-3 -6-2x-3x-x^2 = 0
-9-5x = 0
-5x = 9
x = -9/5
2007-06-04 06:31:12 · answer #4 · answered by Sam 2 · 0⤊ 0⤋
no1.
2x^2 + x -2x - 2 = 2x - 2
2x^2 - 3x = 0
so x = 0 or 3/2
no2.
2x^2 - x + 4x -2 = 2x^2 +6x
3x = -2
so x = -2/3
no3.
x^2 -3 = x^2 + 5x +6
5x = -9
so x = -9/5
2007-06-04 06:26:16 · answer #5 · answered by Mock Turtle 6 · 0⤊ 1⤋
A
x(2x+1)-2(x+1)=2(X-1)
2x^2+x-2x-2 = 2x -2
2x^2-3x=0
x(2x-3)=0
x = 0 or 2x-3 = 0
x = 3/2 = 1.5
B
(x+2)(2x-1)=2x(x+3)
2x^2-x+4x-2 = 2x^2+6x
0 = 3x + 2
-2/3 = x
C
x^2-3=(2+x)(3+x)
x^2-3=x^2+5x+6
0 = 5x+9
x = -1.8
2007-06-04 06:24:17 · answer #6 · answered by Kuan T 2 · 0⤊ 2⤋
1. 2x^2+x-2x-2=2x-2
2x^2-3x=0
x(2x-3)=0
so x=0 or x=3/2
2. 2x^2+4x-x-2=2x^2+6x
3x+2=0
x= -2/3
3.x^2-3=6+3x+2x+x^2
5x+9=0
x= -9/5
2007-06-04 06:25:07 · answer #7 · answered by sweet n simple 5 · 0⤊ 1⤋