2007-06-03 23:12:53 · 7 answers · asked by vivek k 1 in Science & Mathematics ➔ Mathematics
We know that
Sin(A+B)=sinA cosB +cosA sinB
Now,putting B=A in the above formula,we get
sin(A+A)=sinA cosA+cosA sinA
or,sin 2A=2 sinA cosA (Proved
2007-06-03 23:22:40 · answer #1 · answered by alpha 7 · 1⤊ 1⤋
Yes, and cos2A = cos^2 A - sin^2 A
2007-06-03 23:44:53 · answer #2 · answered by nayanmange 4 · 0⤊ 0⤋
sin2A= 2sinA*cosA
L.H.S = sin 2A
= sin ( A + A )
= sinAcosA + cosAsinA
= 2sinA cosA =R.H.S
2007-06-03 23:33:18 · answer #3 · answered by muhamed a 4 · 0⤊ 0⤋
sin (A + A) = sin A.cos A + cos A.sin A
sin (A + A) = sin A.cos A + sin A. cos A
sin 2A = 2.sin A.cos A
2007-06-04 00:50:52 · answer #4 · answered by Como 7 · 0⤊ 0⤋
sin 2A
=sin (A+A)
=sin A cos A+ cos A sin A
=2sinAcosA
2007-06-04 00:24:23 · answer #5 · answered by c 3 · 0⤊ 0⤋
yes
2007-06-03 23:26:36 · answer #6 · answered by mathfreak 1 · 0⤊ 1⤋
yup
2007-06-03 23:15:05 · answer #7 · answered by TENBONG 3 · 0⤊ 1⤋