In how many ways can 15 gifts be distributed equally :
a) among Ada, Beda and Ceda
b)into three parcels of five gifts each
2007-06-03 21:13:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm not sure I understand what you wan't for a. For b however,
The first person can choose 5 gifts from 15.
The second person can choose 5 gifts from 10.
The last person gets the remaining 5 gifts.
Let N = Number of ways
N = (15C5)*(10C5)*(5C5) = (15C5)*(10C5)*1
N = (15C5)*(10C5)
2007-06-03 21:19:25 · answer #1 · answered by Northstar 7 · 0⤊ 1⤋
a) I think it works this way: each would get 5 gifts so the possibilities are represented by 5x5x5 = 125 possible ways to distribute them. Although I'm not sure if it would actually be 15x14x13. sorry
b) I think this would be the same, ie. 3 parcels is equivalent to distributing them to three people.
2007-06-03 21:24:37 · answer #2 · answered by hornedphrog 2 · 1⤊ 1⤋
It's only one way i guess. 5 each to ada, berad and ceda...
2007-06-03 22:15:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a - one way
b - one way
2007-06-03 21:58:53 · answer #4 · answered by Anonymous · 1⤊ 1⤋