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Still helping the children! Thankgoodness this is these last few questions posted are the last questions that I need help with to help them! If you can, I would really appreciate it if you look at my other questions! The stuff they have to learn today makes my eyes cross! Please put all of the work and any formula you had to do as part of your answer, I need it to understand and then further explain it to him! Thankyou for all of the help.
(I had to create this account because my other one isnt working very well, Thanks)

The point ( - 6, 8 ) lies on the terminal arm of ∠A in standard position. Find sin A and cos A.

Best explained (and hopefully correct!) answer gets the points.

2007-06-03 19:42:30 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

angle between 0,0 and -6,8.
find the slope, that is the value of tanA.
from there i guess u can find the other values

2007-06-03 19:50:31 · answer #1 · answered by Charu Chandra Goel 5 · 0 0

A lies in 2nd quadrant.
sin A = 8 / 10 = 4 / 5
cos A = - 6 / 10 = - 3 / 5

2007-06-04 11:09:38 · answer #2 · answered by Como 7 · 0 0

Okay, if the point it (-6,8) and that is at the end of the arm, you can use the arm, the x-axis and the height to create a triangle. Thehorizontal side is equal to 6 units, the verticle side is 8 units. Use pythagorian thearum, a sqaured + b sqaured = c sqaure to get hypotenuse of 10 units.

Using SOH CAH TOA (sin opp hyp cos adj hyp tan opp adj) you can find the sin and cos of the created angle.

Now, sina = opposite side / hypotenuse .... vert/hypot....8/10 or 4/5.

Cosa = adjacent side /hypotenuse....horizontal/hypot....6/10 or 3/5

best i can do without drawing a picture.

2007-06-04 02:51:43 · answer #3 · answered by Anonymous · 0 0

not done this part yet

2007-06-04 03:02:33 · answer #4 · answered by abhilasha b 2 · 0 0

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