Factorising?

2 ⤊

Need help with these:
Factorise the following:

x^3+8

and

(x^4-27x)

Thanks

2007-06-03 19:15:12 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

x^3 + 8

=(x)^3 + (2)^3

=(x + 2)(x^2 -2x +4)
--------------------------------

x^4 -27x

=x(x^3 -27)

=x((x)^3 - (3)^3)

=x(x - 3)(x^2 +3x +9)

2007-06-03 19:22:02 · answer #1 · answered by chancebeaube 3 · 1⤊ 0⤋

x^3+8

FACTORED: (x + 2)(x^2 - 2x + 4)

x^4 - 27x

FACTORED: x(x - 3)(x^2 + 3x + 9)

2007-06-04 02:32:56 · answer #2 · answered by Rey Arson II 3 · 1⤊ 0⤋

here is goes
x^3+8=(x+2)(x^2-2x+4)

and

x^4-27x=x(x^3-27)=(x^2+3x+9)

2007-06-04 02:25:12 · answer #3 · answered by Víctor V. 2 · 0⤊ 1⤋