If a bullet is fired at from a shoulder height at 4 m, totally parralel to the ground, then how long...?

Question

If a bullet is fired at from a shoulder height at 4 m, totally parralel to the ground, then how long will it take for it to hit the ground?

It's the same thing as dropping a bullet from 4m high so there are no obstacles in front of the bullet.

Please show your working out and don't do it if you don't know how.

PS The bullet is fired on Earth so it falls at 9.8m/s^2

Answer 1

s = at²/2 => t = √(2s/a) = √(2*4/9.8) = .9035 sec.

But it you don't like that answer, you put down whatever you want. If you're really 4m tall at the shoulder, then I am --not-- gonna get into a fight with you ☺

Answer 2

This problem obviously involves PROJECTILE MOTION and since you only want the TIME it takes for the bullet drop, we only have to solve for the Y-COMPONENT of the motion.

You can solve this using KINEMATIC EQUATIONS.

Since you're given the following:
height (X init)=4
acceleration(a)=9.8
X final=0
V init=0 (because the initial velocity of the Y-component is always zero)

use X final = X init + (V init)(t) + [1/2(a)(t)^2]

0=4+ [1/2(-9.8)(t)^2]

t=0.903 second or 1 sec

Answer 3

given that height h = 4m
g = 9.81m/s
now
as the bullet is fired parallel to the ground its initial velocity alony y axis is 0
thus the tiem required to hit the ground it found as follows
4=9.81 *.5 * t * t
hence t = (4/(9.81*.5))^.5
t=.903 sec

Answer 4

you put the answer, aside from actually doing the math, in your question....

BTW... where do you find someone who is 4 m tall at the shoulder? The average person is just a bit over 1.5 meters at the shoulder.

Answer 5

you just can't solve that with just the info you given

it depends on what gun, where on earth you are, the weather, the day, etc

your question is vague