64 meters?
2007-06-03 18:01:44 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Calculate the time the rock takes to fall 64 meters using basic kinematics equations.
Yf - Yi = ViT + .5aT^2
64 = .5 (9.8 m/s/s) T^2
T = 3.6 seconds
plug that in for the runner:
Xf - Xi = ViT + .5aT^2
Xf = (9 m/s)(3.6 s)
The sprinter travels 32.4 meters.
2007-06-03 18:08:51 · answer #1 · answered by darkhydra21 3 · 0⤊ 0⤋
first you need to find the time it takes the rock to hit the ground and assume the rock falls from rest.
y = 1/2at^2
solve for t
t = sqrt (2y / g)
y = sqrt(64*2 / 9.8)
t = 3.614s
x = vt
x = (9) (3.614)
x = 32.5m
2007-06-03 18:11:55 · answer #2 · answered by 7 · 1⤊ 0⤋
s=at²/2 => t=√(2s/a) = √(2*64/9.8) = 3.614 s
3.614s * 9 m/s = 32.526 m
Doug
2007-06-03 18:07:53 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
How high is the rock falling from? I dont understand.
2007-06-03 18:05:11 · answer #4 · answered by Steven D 1 · 0⤊ 0⤋