Stumped...
An 835 N sled is pulled a distance of 200 m. The task requires 1.20 x 10^4 J of work and is done by pulling on a rope with a force of 125 N. At what angle is the rope held?
2007-06-03 14:45:22 · 3 answers · asked by movin2thabeeet 1 in Science & Mathematics ➔ Physics
F= W/d
F - force applied and parallel to the path
W- work done by force F
d - displacement (distance covered in a particular direction)
Angle = arcCos( F/ Ft)
F= 1.20 x 10^4/200= 60N
Angle = arcCos( 60/ 125)
Angle= 61.3 deg
2007-06-03 14:52:37 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
If θ is the angle between the force applied (125N) and the actual force needed to pull the object then
125 cos θ = F ( the force needed.)
Work done = force x displacement
12500 = 125 cos θ * 200.
Cos θ = 12500 / 25000 = 0.5.
θ = 60 degree.
2007-06-03 15:28:45 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
Work = force * distance
1.2 x 10^4J = force * (200)
force = 60N
60N is the force that is applied horizonally to the sled.
use trig to find the angle
cos^-1 (60/125) = 61.31 degrees
2007-06-03 14:58:15 · answer #3 · answered by 7 · 0⤊ 0⤋