English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A solenoid is 15cm long and has 250 turns. What is the magnetic field strength inside the solenoid if the current in the coils is 3.8A?

Please show explanation and if it helps, the answer is 8.0 x10^-3 T

2007-06-03 14:36:08 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

B = μ N I = μ (n / L) I

where μ = 4 pi E-7
N is the number of turns per meter
I is the current in amperes.

B = μ N I = 4 pi E-7 x (250/.15) x 3.8
B= 8.0 E -3 Tesla

2007-06-03 15:00:53 · answer #1 · answered by Edward 7 · 1 0

fedest.com, questions and answers