Im haveing a hard time with this math problem please help?

Question

a=-4, b=2, c=-3

c[2(b+3a)+10]=???????

Answer 1

start from the inside out..

-3[2(2+3(-4))+10]

-3[2(2-12)+10]

-3[2(-10)+10]

-3[-20+10]

-3(-10)

=30

Answer 2

Plug 'n Play

-3[2(2+3(-4)) +10]

Remember PEMDAS Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. The order in which you do operations.

-3[2(2+3(-4)) +10] =

-3[2(2-12) +10]=

-3[2(-10) +10] =

-3[-20 +10] =

-3[-10] =

30

Answer 3

First replace a, b, and c:
-3[2(2+3*-4)+10]
Then begin simpifying from the inside out:
-3[2(2-12)+10]
-3[2(-10)+10]
-3[-20+10]
-3[-10]
30

Answer 4

30

Answer 5

-3 [2(2+3(-4)+10] = ?
-3[2(2+ (-12))+10] + ?
-3[-20+10] = ?
-3[-10] = ?
30

Answer 6

c[2(b+3a)+10]
= -3[2(2+3*(-4) +10]
= -3[2(2-12)+10]
=-3[-20+10]
=-3[-10]
=30

Answer 7

the answer is 114: 3[2(2+3*4)+10]
3[2(14)+10]
3[38]
=114

Answer 8

easy just plug in the number for the variables, so if c= 3 then in the equation it would be 3[2(b+3a)+10] then for be plug in 2 and a is 4, then solve but remember PEMDAS (parenthesis, exponents,multiplication,division,addition and substraction) those are the order. So fisrt solve for the parenthesis 3[2(14)+10] then you have another parenthesis solve for it 3[38] then it will be 114 I CAN' TELL IF IT'S -3 OR 3but this is how you solve it

Answer 9

The directions are as follows: start by filling in the a, b & c values. 2nd start the (), multiply (3a) then add b. Next step is mulitply your answer by 2 then add 10. Last is the brackets, mulitply by c. I hope this helps, without my answering the problem for you. Sorry, just the teacher in me.

Good luck!

Answer 10

3[2(2+12)+10]
3[ 2(14)+10]
3[28+10]
3[38]
=114