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2007-06-03 12:56:50 · 2 answers · asked by Krysta 1 in Science & Mathematics Mathematics

2 answers

integral (0 to -1) e^(-x) dx
= (-1)e^(-x) from 0 to -1
= (-1)e^1 - (-1)e^0
= - e + 1
= 1 - e

2007-06-03 13:01:14 · answer #1 · answered by Kemmy 6 · 0 0

e^-1-e^0 = 1/e-1 =(1-e)/e

2007-06-03 13:01:57 · answer #2 · answered by ironduke8159 7 · 0 0

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