(3a + 2b)^3 (3a + 2b)^-2
I got (9a^3 + 6b^3) (-6a^-2 + -4b^-2) = -54a + -24b
but the answer is 3a +2b.
What did I do wrong? Can you write out and explain how you arrive at 3a +2b? Thanks very much.
2007-06-03 11:51:31 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(3a + 2b)^3 (3a + 2b)^-2
=(3a + 2b)^(3+-2)
=(3a + 2b)^1
=3a + 2b
2007-06-03 11:55:28 · answer #1 · answered by Anonymous · 1⤊ 0⤋
You worked too hard. It is simply x^3/x^2
or ((3a + 2b)^3)/ (3a + 2b)^2 = (3a + 2b)
.
2007-06-03 18:57:31 · answer #2 · answered by Robert L 7 · 1⤊ 0⤋
Ok, let's see
[(3a+2b)(3a+2b)(3a+2b)]/[(3a+2b)(3a+2b)] = 3a+2b
Hope this explanation helps.
2007-06-03 18:56:00 · answer #3 · answered by alrivera_1 4 · 0⤊ 0⤋
You misinterpreted the exponential. For any quantity z, z^3 times z^-2 is simply z.
2007-06-03 18:54:49 · answer #4 · answered by Anonymous · 0⤊ 0⤋