How do you find the molar concentration of 1.00 L of solution containing 100.0g of glucose, C6H12O6?

Question

Thank you.

Answer 1

Molar concentration = mol / liters of solution

First get moles of glucose...

100 g glucose / 180.18 (g/mol) = 0.555 mol glucose

Molarity = mol / liters
Molarity = .555 mol/1.00 L = 0.555 M glucose solution

Answer 2

You look up the molecular weight of carbon, hydrogen and oxygen. Multiply the weight of carbon by 6, that of H by 12, and that of O by 6. That number, in grams, would be the amount of glucose that would be dissolved in one liter to make a 1 molar solution of glucose. To find out the molarity the soution containing 100 grams in one liter is, divide 100 by the number of grams in one molar. The resulting fraction is the molarity of the solution you have.

Answer 3

properly molarity M=mols of solute/L of answer. So in my chem classification my instructor taught us to coach dimensional prognosis. 40.0g C6H12O6/ a million. Then a million mol C6H12O6/ a hundred 80.18 g C6H12O6. Then there is .4 L by way of certainty 4 hundred mL/one thousand= .4. So all mutually that's truthfully 40/a hundred 80.18•.4= .555 M.

Answer 4

Do you understand the terms "molar concentration" and "moles"?

The molecular weight of a substance expressed as grams is called the gram molecular weight or simp[ly the "molecular weight"..

A mole of a substance is 1 gram molecular weight. If a substance has a molecular weight of 18, then a 1.000 mole of a substance is equal to 18 grams.

The molar concentration is the number of moles of a substance contained in 1 liter of solution.

1) determine the molecular weight of C6H12O6
2) determine how many moles 100 grams represent (gm/MW)
3) The molar concentration is simply the number of moles in 1.00 liter of solution.

Answer 5

First find the number of moles of C6H12O6:

(100.0g C6H12O6)((1 mol C6H12O6)/(6*12.011 + 12*1.008 + 6*15.999 g C6H12O6)) = 0.5551 mol C6H12O6

Molar concentration = mol / L = 0.5551mol / 1 L

Using sig figs, your answer is: 0.555 M