16=x(x-6)
2007-06-03 09:44:13 · 9 answers · asked by Dieune P 1 in Science & Mathematics ➔ Mathematics
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2007-06-03 09:48:49 · update #1
16=x(x-6)
16=x^2-6x
x^2-6x-16=0
(x-8)(x+2)=0
x=8 or -2
2007-06-03 09:47:39 · answer #1 · answered by UnknownD 6 · 0⤊ 1⤋
Multiply the x through:
16 = x^2 - 6x
Move the 16 to the other side.
0 = x^2 - 6x - 16
Factor (either by looking at it or the quadratic forumula)
0 = (x - 8)(x + 2)
Which means x = 8 or -2
2007-06-03 16:49:16 · answer #2 · answered by rebkos 3 · 0⤊ 0⤋
x=8
2007-06-03 16:47:00 · answer #3 · answered by Anonymous · 0⤊ 1⤋
10
2007-06-03 16:46:44 · answer #4 · answered by Anonymous · 0⤊ 1⤋
16=x(x-6)
Expand and subtract 16 from both sides
x² - 6x - 16 = 0
(x - 8)(x + 2) = 0
x = 8, x = -2
.
2007-06-03 16:48:53 · answer #5 · answered by Robert L 7 · 0⤊ 0⤋
16=x(x-6) first distribute the x
16=x^2'-6x then set the equation = to 0
x^2-6x-16=0 then factor
(x-8)(x+2)=0 lastly, if u have to solve for x, set up 2 separate equations...
x-8=0, x+2=0
x=8 or x=-2
2007-06-03 16:48:28 · answer #6 · answered by Anonymous · 0⤊ 1⤋
x^2-6x-16
(x-8)(x+2)
x-8=0 and x+2=0
There are 2 answers
x=8 and -2
2007-06-03 16:55:36 · answer #7 · answered by Rich C 2 · 0⤊ 0⤋
8?
2007-06-03 16:47:19 · answer #8 · answered by emma 3 · 0⤊ 1⤋
yes...what's wrong with that. it is an equation. so multiply out the bracket ...... it gives u x squared minus 6x.
2007-06-03 16:48:14 · answer #9 · answered by Seungyong W 5 · 0⤊ 1⤋