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I cannot understand this problem. Please help me :( I would appreciate it a lot. Thank you much.

In the model of the hydrogen atom, an electron in the lowest energy state moves at a speed of 2.17 x 10^6 m/s in a circular path having a radius of 5.34 x 10^-11 m. What is the effective current associated with the orbiting electron (in mA)?

I know that R = V/I, but I don't have anything to work with :(

2007-06-03 09:15:15 · 2 answers · asked by Hotaru 1 in Science & Mathematics Physics

2 answers

The angular velocity of the electron is w = v/r; where v = 2.17 X 10^6 m/sec and r = 5.34 X 10^-11 m. Solve for w, which is in radians per second (rad/sec); where rad = 360 deg/2 pi.

Now pick an arbitrary point on the orbit and call that t = 0 point. Mutiply w by one second so that theta = wt = w; that's the number of radians the electron of 1 coulomb charge travels in that one second. Divide theta by 2 pi so that theta/2 pi = f = frequency of the electron in orbit. Then multiply the frequency by Q = 1 coulomb so that I = Qf equals the current in amperes = 1000 mA. You can do the math.

2007-06-03 10:42:32 · answer #1 · answered by oldprof 7 · 0 0

Remember that current is defined as charge per second. So to solve this problem you have find frequency(units of 1/s) of the electron orbiting the atom and then multiply this by the charge of the electron.

2007-06-03 16:20:56 · answer #2 · answered by sparrowhawk 4 · 1 0

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