please show me how to do this problem thanks!!!?

Question

If 3b2 - 2^b - 16 represents the area of a rectangle, what is the perimeter of that rectangle?
A) 4b - 12

B) 8b - 6

C) 8b - 12

D) 4b - 6

Answer 1

Okay rectangle area = length x width
So if you factor 3b^2 - 2b - 16, think of one term as the length and the other as the width. Factoring this polynomial gives you the following:

(3b-8)(b+2) where (3b-8) is the length and (b+2) is the width, or the other way around.

The perimeter of a rectangle is P = 2*(length + width). So for this problem, add the two terms together, then multiply them by two.

P = 2 *(l+w) = 2((3b-8) + (b+2))= 2(4b-6)= 8b-12, which is answer choice (c). HTH

Answer 2

The area is the product of the width and length of the rectangle. Just factor the expression to find the width and length. The formula for the perimeter of a rectangle is:

P = 2 ( w + l).

After you find w and l, just plug them into the above formula and crank out the answer.

3 b² - 2 b - 16 = (3 b - 8)(b + 2)

In this case, it doesn't matter which is the width or the length. Now, just plug them into the formula:

P = 2 [(b + 2) + (3 b - 8)].
P = 2 (4 b - 6)
P = 8 b - 12

C is the answer.

Answer 3

The answer is c

Factorising it we get
3b^2-8b+6b-16
So3b(b+2)-8(b+2)
so factors are (b+2) (3b-8)

These are the 2 sides of the rectangle
So the perimeter is
p=2(l+b)
= 2(b+2) +2(3b-8)
=2b+4+6b-16
=8b-12

Answer 4

you set the equation equal to zero and solve for b.
This gives you (3b-8)(b+2). So 3b-8 can be assumed as the length and b+2 as the width (although it doesnt matter which way you do it) so you multiply both by two (since there are four sides total) and add.

C is the answer