AB = 6cm
BC = 4cm
AC = 3cm
2007-06-03 06:56:22 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1)AB = 6cm BC = 4cm AC = 3cm
2)AB = 8cm BC = 4cm AC = 3cm
3)AB = 5cm BC = 11cm AC = 6cm
4)AB = 4cm BC = 4cm AC = 7.5cm
2007-06-03 07:22:29 · update #1
Actually you cannot have a triangle, obtuse or otherwise with those lengths. Now there is a right triangle with the dimensions of 3,4,5. There fore the side AB of 6cm is wrong,
It should be 5cm. This can be verified with Pythagorean theorem a^2+b^2=c^2 (3^2=9 + 4^2=16 = 5^2=25) 9+16=25
2007-06-03 07:10:57 · answer #1 · answered by jeff52478 1 · 0⤊ 0⤋
You've only given one set of dimensions. This sounds like a multiple choice question, of which the dimensions you gave are one choice. The way you determine if lengths are possible sides of a triangle is to add the two smaller ones - if the sum is greater than the third side then you have a triangle. The difference of the two bigger ones also must be less than the smallest.
2007-06-03 14:06:48 · answer #2 · answered by Linda O 1 · 0⤊ 0⤋
Well, you've only given us one set of dimensions, but 6, 4, 3 makes a perfectly good obtuse triangle.
2007-06-03 14:00:59 · answer #3 · answered by jsardi56 7 · 0⤊ 0⤋