math question?

Question

What are the zeroes (solutions) of the polynomial function

f(x) = (x + 7) squared (x - 3)

and how did you get that answer?

Answer 1

-7, and 3
put x+7=0
-7 -7
x=-7
put x-3=0
+3 +3
x=3

Answer 2

you know the zeros are the point(s) the polynomial crosses the x axis, so what number will make both expressions zero? By adding a (-7) to x + 7 you get one zero and adding a (+3) to x - 3 you get the other one. I do better by looking at problems conceptually rather than just looking at them algebraically.

Answer 3

The roots are -7,-7, and 3
-7 is a repeated root
this is how you solve it
(x+7)^2=0 ===> x=-7
(x-3)=0 =====> x=3

Answer 4

f(x)=(x+7)^2(x-3)

You can substitute in 0 for f(x) since you are trying to find the solutions of the function. In other words, The solutions (x-intercepts) are found when f(x)=0.

So,
0=(x+7)^2(x-3)

Set each part equal to zero.
(x+7)^2=0
x-3=0

Solve.
x+7=0
x=-7

x-3=0
x=3

Your solutions are x=-7 and x=3, or {-7,3}

Answer 5

x = -7, x = 3
set (x+7)^2 = 0
and (x-3) = 0

So, you get x = -7 and x = 3

Answer 6

y=f(x) = (x + 7) squared (x - 3)

(x-3)lny=ln(x+7)

lny=ln(x+7)/(x-3)

y>0
x+7>0
x>-7
x-3 can not be zero
hence x can not be 3

if x=0
then lny=ln7/-3
-3lny=ln7
1/y^3=7

y^3=1/7

Answer:
y=cube root of (1/7)