English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

the ? says: write an equation in standard form of the line with slope 2/5 and going through (-3,6). Please help! the final is tomorrow and I can only miss 5 ?'s to get an A for the quarter!

2007-06-03 06:30:13 · 9 answers · asked by arledgetd 4 in Science & Mathematics Mathematics

9 answers

Hi,

Your other answers don't know what standard form is for a linear equation.

The standard form of a linear equation is Ax + By = C, where A, B and C are integer values. (As a teacher, I also prefer that A is positive.)

To find that form, start with slope-intercept form, y = mx + b. Fill in the slope value for m and the x and y coordinates of the point for x and y. Then solve for b, which is the y intercept.

y = mx + b
6 = (2/5)(-3) +b
6 = -6/5 + b
36/5 = b

So the slope-intercept form of the line is y = 2/5x + 36/5.

To change this into standard form, multiply everything by 5 to eliminate the fractions.

y = 2/5x + 36/5
5(y = 2/5x + 36/5)
5y = 2x + 36

Now to put terms in order for standard form, Ax + By = C, subtract 2x and put it first on the other side.

5y = 2x + 36

-2x + 5y = 36 This could be the answer. However, I'd multiply
it by -1 to switch all the signs.

-1(-2x + 5y = 36)

2x - 5y = -36

The answer in standard form: 2x - 5y = -36

I hope that helps!! :-)

PS If you want to mark me as a contact, I'll check back here off and on today to see if you have any other questions you need help with.

2007-06-03 06:50:49 · answer #1 · answered by Pi R Squared 7 · 1 0

Standard form for a straight line is going to be

y = ax+b, where "a" is the gradient (which we have = 2/5) and some constant. We have a coordinate that we know is on the line (-3,6)

y=ax+b

x=-3, y=6, a=2/5

putting in the numbers

6 = 2/5*(-3) + b

b = 6 -( 2/5*(-3)) = 6 - (-6/5) = 6+6/5 = 7 1/5, or 7.2

Put back into the equation to make sure (2/5 = 0.4):

0.4*(-3) + 7.2 = -1.2 + 7.2 = 6, the answer we expect.

2007-06-03 06:37:45 · answer #2 · answered by davidbgreensmith 4 · 0 1

Standard Form:
Ax+By=C

Where the GCF of A, B, and C is 1
and A and B are integers and A>1

First to find out the equation of the line we use point slope form:
y-y2=m(x-x2)
where m=slope and y2 and x2 refer to a point (x2,y2)

So, in here, m=2/5 and (x2, y2)=(-3,6)
Point slope form:
y-y2=m(x-x2)

plug in
y-6=2/5(x-(-3))
y-6=2/5(x+3)
y-6=2/5x+6/5
y=2/5x+6+6/5
y=2/5x+30/5+6/5
y=2/5x+36/5

Now we use standard form.
Ax+By=C

To get y=2/5x+36/5 into Ax+By=C, we first subtract 2/5x on both sides.

-2/5x+y=36/5

Next, multiply through by -1 because A cannot be negative
2/5x-y=-36/5

Last, A has to be an integer so we multiply through by 5.

2x-5y=-36

The GCF of 2,5 and -36 is 1, so it is in Standard Form.

EDIT:

guys, y=mx+b is SLOPE-INTERCEPT FORM, not STANDARD FORM!

2007-06-03 06:38:56 · answer #3 · answered by cheesysoundeffectz 2 · 0 0

Let's start by putting the line in point-slope form, since that's what we're given. (y-6)=(2/5)(x+3). Multiply through by 5 to get:

5y - 30 = 2x + 6
-2x + 5y = 36
2x - 5y = -36

Now 2,5, and 36 have no common divisors, so it is in standard form.

2007-06-03 06:40:28 · answer #4 · answered by TFV 5 · 1 0

ok, standard form is y = mx + b where m is the slope, b the y-intercept. so, you have the slope and a point, plug all those in and solve for b:

6 = (2/5)(-3) + b
b = 36/5

standard form is: y = (2/5)x + 36/5

2007-06-03 06:37:06 · answer #5 · answered by emp211 3 · 0 2

y - 6 = (2/5).(x + 3)
y - 6 = (2/5).x + 6/5
y = (2/5).x + 6/5 + 30/5
y = (2/5).x + 36/5
This is in form y = mx + c
where m = (2/5) and c = (36/5)

2007-06-03 07:03:34 · answer #6 · answered by Como 7 · 0 0

Sloope intercept Form

y = mx + b

Ordered pair

(- 3, 6)

slope

2/5

- - - - - -

6 = 2/5(- 3) + b

6 = - 6/5 + b

6 + 6/5 = - 6/5 + b + 6/5

30/5 + 6/5 = b

36/5 = b

- - - - - - - - -

The equation

y = 2/5x + 36/5

- - - - - - - -s-

2007-06-03 07:32:10 · answer #7 · answered by SAMUEL D 7 · 0 1

Each line with slope l that goes through point A(x1,y1) has an equation of the form:
y-y1=l(x-x1)

Therefore your line is:
y-6=2/5*(x+3)

2007-06-03 06:39:12 · answer #8 · answered by geo_topos 1 · 0 2

The 'time-honored sort' for an imaginary extensive type is i*b the place i is the imaginary unit (sqrt(-a million) and b is the fee of the imaginary fee expressed as a 'established' (or actual) fee. The i is often written first to 'alert' the reader that what follows is an imaginary fee. additionally, in electric powered engineering, the j is often used for the imaginary unit because of the fact a decrease case i is used for instantaneous contemporary. understand that sqrt(a*b) = sqrt(a) * sqrt(b) so....... on your problem, factor out the -a million from each and all the radicals and write the imaginary fee as i*(2*sqrt(40 9) + 3*sqrt(sixty 4)) and simplify it to i*(2*7 + 3*8) = i*38 Doug

2016-10-09 09:15:53 · answer #9 · answered by ribbs 4 · 0 0

fedest.com, questions and answers