Physical Science Final Exam Help?

Question

I was going over my study sheet, and i need help with one thing i cant seep to find: "Describe how gravity affects satellite motion and planetary motion" i looked in my book and online.....will you help me?

Answer 1

With planets and satelites that have a stable orbit, gravity exactly cancels out the "centrifugal" force or the tendency of the satelite to continue in a straight line and fly off into space.

Answer 2

Satellites and planets are bound by the same kind of forces: weight and centrifugal/centripetal. They stay in orbit around their centers of revolution when f = ma = (W - F) = 0; where satellite/planet weight W is exactly counter acted by F, the centrifugal force acting on the orbiting body of mass m. Here's why:

When f = ma = 0, it follows that acceleration (a) along the radius of curvature of the orbit is zero. Clearly, m > 0 always; so it has to be a = 0 when the net radial force on the orbiting body is zero.

When a = 0, there is no change in velocity along the radius, either into or away from the center of the curve, which is the orbital path. In other words R, the radius length, remains constant. Thus, the fixed distance from the center of curvature means the satellite or planet will neither crash into or leave the body it is orbiting. It will continue to orbit.

So, to answer your question, gravity affects orbital body motion by determining the weight (W) that has to be offset by centrifugal force (F). Put it simply, more W means more F, and less weight means less F. Because the two forces are in balance when a body is in orbit, we can write W = mg = mv^2/R = ma = F; where v is the so-called tangential velocity of the orbiting body.

From above, we find g = v^2/R or R = v^2/g, which clearly shows that the orbiting radius depends on g the acceleration due to gravity. Thus, we can say that gravity directly determines how far away the orbiting body needs to be to stay in orbit at a given velocity (v).

Answer 3

a million. carbon-12 and carbon-14 are "isotopes" of one yet another their chemical image would be written as "12C" (12 in superscript at left hand or good hand ingredient ) and "14C" (additionally in large script at left hand or good hand ingredient because it is the atomic mass style of carbon isotopes aka isotopic mass) and that they each and each have carbon - 12 ___"6"___ protons, ___"6"___ neutrons, and ___"6"___, electrons and carbon - 14 ____"6"____ protons, ____"8"___neutrons, and ____"6"___ electrons. (considering the fact that no. of protons = no. of electrons yet no. of neutron would selection and that's what makes them isotopes! ) 2. Atomic Mass Unit is one "divided via 12th the burden " of a carbon - 12 atom. 3. the place do you hit upon the Valence Electrons a million,2,3,4,5,6,7,8? valence electrons are electrons got here upon interior the outer maximum shell of a area, periodic table's communities (vertical columns) are categorized in accordance to valence electrons of the climate. Like, Ist team factors; hydrogen, lithium, sodium, potassium and so on all have a million valence electrons.... merely view a periodic chart and notice the team sequentially and notice the climate having a million,2,3,4,,5,6,7,8 valence electrons in 1st, 2nd, third, 4th, 5th, 6th, seventh, 8th team respectively... 4. Water being replaced to hydrogen and oxygen gasoline. desire some extra element in this question, are u inquiring for a reaction/chemical equation right here or description, what, plz upload.. 5. maximum reactive atoms have what proportion Valence Electrons? the main reactive factors have the two a million valence electron or 7 valence electrons through fact 1st team factors called alkali metals are very reactive like sodium Na , and seventh team i.e Halogen team or Halogen kinfolk are merely as reactive and commonly the main reactive ones fairly Fluorine F is the main reactive....and as they are from 1st and seventh team their valence electrons are a million and seven respectively, thats ehy maximum reactive atoms are having a million or 7 valence electrons of their outermost shell....

Answer 4

No. 2pts.