Probably a typo in the problem statement .
Or else it would read 5w - 20 - xw ;
Should be : 5w - 25 - xw + 5x
You could factorise something even if it were not quadratic , like :
5w - 25 - xw + 5x = w (5 - x) - 5 ( 5 - x) = (w - 5)(5 - x)
I suppose a "x" was dropped in the last term .
2007-06-03 05:34:17
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answer #1
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answered by Duke_Neuro 2
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First, let's do the easy bit: -25 + 5 = -20. So now we have:
5w - xw -20. This can be further simplified to: w(5 - x) -20.
Somebody has put this in the form of an equation w(5 - x) = 20. Whilst this is perfectly correct, if you are asked to factorise something, it's normally considered correct to leave it in it's original form.
2007-06-03 10:16:18
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answer #2
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answered by brainyandy 6
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First, look for common factors between 2 of the terms, and rearrange the question.
Then you take out the common factors for each pair.
In your question, I believe that you must have made a typo.
5w-25-xw+5
= 5w-xw-20 (cannot be factorised as there aren't any common terms between the 3 of the terms.)
2007-06-03 05:39:16
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answer #3
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answered by Kemmy 6
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Assuming 5w-25-xw+5=0
combine like terms
5w-20-xw=0
then rearrange
5w-xw-20=0
then factorise
w(5-x)-20=0
which can be rewritten as:
w(5-x)=20
2007-06-03 05:42:50
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answer #4
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answered by Sammi 2
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To factorise is to take out common factors.
In this the common factor is 5
5(w-5 -xw+1)
2007-06-03 05:23:05
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answer #5
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answered by Anonymous
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The only thing you can do is simplify by combining like terms. 5w - xw - 20.
2007-06-03 05:25:04
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answer #6
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answered by TychaBrahe 7
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The expression does not seem to be factorised.
2007-06-03 05:25:25
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answer #7
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answered by path22by7 1
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divide through by 5
so you get
5(w-5-xw/5+1)
2007-06-03 05:39:36
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answer #8
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answered by ~*tigger*~ ** 7
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