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If I have this problem: p^4/18m^6(27m^3) how can i simplify this expression

2007-06-03 05:08:07 · 5 answers · asked by Overclokr 1 in Science & Mathematics Mathematics

(p^4) / (18m^6)(27m^3)

2007-06-03 05:23:29 · update #1

5 answers

Is the 27m^3 multiplied to the numerator? If so, you can cross out the m^3 and divide the denominator by m^3, leaving m^3 in the denominator. You can also divide the 27 and 18 by 9 to leave 3 in the numerator and 2 in the denominator.

3p^4/2m^3

2007-06-03 05:16:02 · answer #1 · answered by TychaBrahe 7 · 0 0

You can simplify this in the following way :
p^4/18m^6(27m^3)
=p^4/(18*27)(m^6*m^3)
=p^4/486*m^(6+3)
=p^4/486m^9

2007-06-03 05:18:48 · answer #2 · answered by path22by7 1 · 0 0

a million. first use the distributive aspects to get 4*5y - 4*3 -2*6y +(-2)*3 then do multiplications to get 20y - 12 -12y - 6 then upload like words to get 8y -18 2. in case you have the comparable base style, on your question that's a 5, then you subtract the exponent interior the denominator from the only interior the numerator so the question will become 5^(3-5) which simplifies to 5^-2 that would additionally be written as a million/5^2 or a million/25

2016-12-30 15:56:01 · answer #3 · answered by ? 3 · 0 0

(p^4)/(18m^6)(27m^3)
= (p^4)/(486m^9)

2007-06-03 05:47:22 · answer #4 · answered by Kemmy 6 · 0 0

your use of only 1 set parenthesis in this question makes it look like Algebra III work...can you rewrite it using more parenthesis.

2007-06-03 05:17:10 · answer #5 · answered by goldenret35 2 · 0 0

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