Find the distance between each pair of points whose coordinates are given?

Question

(9,7),(1,1)

I just need one example cuz I forgot how to do it from Friday!
Thanx!

Answer 1

It's the square root of the sum of the squares of the differences. First you take the difference of the x-coordinates and the difference of the y-coordinates. That's 9 - 1 = 8 and 7 - 1 = 6. Now square them to get 8^2 = 64 and 6^2 = 36. Sum them to get 64 + 36 = 100. Finally, take the square root to get sqrt(100) = 10. The distance is 10.

Answer 2

If you are looking to find the distance between each pair of points that you listed, you simply have to use the distance formula: the square root of (x2-x1) squared + (y2-y1) squared....so, you would do (1-9) squared + (1-7) squared, simplify it: (-8) squared + (-6) squared = 64 + 36 = 100. This works out perfectly, because 100 is a perfect square, so the square root of it is 10. So, 10 is the distance between the two points! (hope this wasnt too confusing!)

Answer 3

delta-y = 7-1 = 6
delta-x = 9-1 = 8

distance^2 = 8^2 + 6^2 (pythagorean theorem)
distance^2 = 64 + 36
distance^2 = 100
distance = 10

Answer 4

d² = (1 - 9)² + (1 - 7)²
d² = 64 + 36
d² = 100
d = 10

Answer 5

distance = sqroot[ (9-1)^2 + ( 7 - 1)^2]
=sqroot[ 64 + 36 ]
= sqroot[ 100]
= 10 units

Answer 6

i aint doing your homework for you!