Factor a^2 - 16.
A) (a + 2)(a - 8)
B) (a - 4)(a - 4)
C) (a + 4)(a + 4)
D) (a + 4)(a - 4)
2007-06-03 03:43:00 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
d
fiol (first inner outer last)
a*a=a^2, a*4=4a, -4*a=-4a, -4*4=-16
a^2-16
or
what two numbers multiply to equal -16 and add upp to be 0.
make a table.
-2, 8
2,-8
4,-4 all multiply to -16
but what two add up to 0
4,-4
2007-06-03 03:46:08 · answer #1 · answered by My point exactly 5 · 0⤊ 0⤋
D) a^2 - 4^2=(a + 4)(a - 4)
2007-06-03 10:46:06 · answer #2 · answered by iyiogrenci 6 · 0⤊ 1⤋
D) (a + 4)(a - 4)
2007-06-03 14:13:49 · answer #3 · answered by muhamed a 4 · 0⤊ 0⤋
its a special case
a^2 is a perfect square and so is 16,
its not a beause if you multiplied it out , you'd get a^2-6a-16.
b would make it a^2-8a +16
c would be a^2+8a+16
it must be d b/c in the problem, the 16 is negitive, there is also no x in it meaning that they had to have canceled eachother oout
the answer is D
2007-06-03 10:54:04 · answer #4 · answered by heartbreakworld 4 · 0⤊ 0⤋
This is practically an identity. Given the equation a^2 - b^2, the factors are (a + b)(a - b), so the answer is D.
2007-06-03 10:47:40 · answer #5 · answered by TychaBrahe 7 · 0⤊ 1⤋
It's the difference of 2 squares. Answer d.
2007-06-03 10:52:25 · answer #6 · answered by Steiner 7 · 0⤊ 1⤋
the answer is D)
2007-06-03 10:47:23 · answer #7 · answered by Anonymous · 0⤊ 1⤋
D
2007-06-03 10:47:50 · answer #8 · answered by maidmaz 3 · 0⤊ 1⤋