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a) 3i
b) -7
c) 4
d) -2i
e) 4+4i

2007-06-03 03:29:39 · 6 answers · asked by Mysara e 2 in Science & Mathematics Mathematics

6 answers

Complex numbers are unordered. There is no largest. -7 has the largest modulus but this is not the same thing as being the largest.

2007-06-03 03:59:23 · answer #1 · answered by Anonymous · 1 0

Answer: b) -7+0i
has max distance from origin.


a) 0+3i
r=3

b) -7+0i
r=7

c) 4+0i
r=4

d) 0-2i
r=2

e) 4+4i
r=sqrt(32)

2007-06-03 10:44:25 · answer #2 · answered by iyiogrenci 6 · 0 0

I suppose 4 is the largest because -7 is definitely below 4 and the rest are imaginary numbers. Imaginary numbers don't actually have a value.

2007-06-03 10:37:37 · answer #3 · answered by UnknownD 6 · 0 0

since i is a positive number than the answer is 4+4i is the largest number. imaginary numbers don't have a definite value but they can be compared with other numbers of course

2007-06-03 10:36:49 · answer #4 · answered by tak_np 1 · 0 1

With complex numbers you cannot specify that z1>z2. you can specify that |z1|>|z2|.

If you are talking about the largest value of |z| given the above possible values of z, the largest value would be with z=-7. in this case |z| = 7

a) |z |= 3
b) |z| = 7
c) |z| = 4
d) |z| = 2
e) |z| = 5.66 (approx)

Largest value of |z| = 7 ---- (b)

2007-06-03 10:41:01 · answer #5 · answered by gudspeling 7 · 0 0

On the complex plane, contrarily to the real line, there's no order relation, so it doesn't make sense to say a complex number is larger than another.

2007-06-03 11:03:26 · answer #6 · answered by Steiner 7 · 1 0

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