Problem: (x y) (x^2 y)^4 = x^12 y^8 or x^9 y^5
2007-06-03 02:37:07 · 7 answers · asked by lanning848 2 in Science & Mathematics ➔ Mathematics
Rules to remember:
1. When multiplying variables with like bases, add the values of the exponents.
2. When raising variables to exponental powers, multiply the numbers.
3. Order of operations say to do exponents first.
So, to simplify:
(xy)(x^2 y)^4 = (xy) (x^8 y^4) = x^9 y^5
2007-06-03 02:43:24 · answer #1 · answered by Mr. Adkins 4 · 1⤊ 0⤋
x^9 y^5
2007-06-03 09:59:31 · answer #2 · answered by anubhavdas 1 · 0⤊ 0⤋
^9 y^5
2007-06-03 09:46:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(xy) (x^2y)4 =
(xy) (x^8y^4) =
x^9y5
Remember;
1) x^n times x^m = x^n+ m
Example:
x^3 times x^5 = x^ 3 + 5 = x^8
2) ( x^n)^m = x^nm
Example
(x^4)^3 = x^ 4 times 3 = x^12
2007-06-03 09:51:25 · answer #4 · answered by detektibgapo 5 · 0⤊ 0⤋
(x^2 y)^4 = x^8 y^4
x^8*y^4 *xy = x^9y^5
2007-06-03 09:47:11 · answer #5 · answered by maussy 7 · 0⤊ 0⤋
x^9y^5
2007-06-03 09:41:03 · answer #6 · answered by s b 3 · 0⤊ 0⤋
(xy)(x^2y)^4
=xy(x^2)^4y^4
=xyx^8y^4
=x^9y^5
2007-06-03 09:45:40 · answer #7 · answered by The Wolf 6 · 1⤊ 0⤋