MATH question?

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what is the value/s of x in
(x² - 5x)log9 3= -2

2007-06-03 01:38:40 · 2 answers · asked by diane s 1 in Science & Mathematics ➔ Mathematics

2 answers

First perform the log function. log (base 9) of 3 = .5
Subsitute .5 in for the log resulting in
(x^2-5x).5=-2

Then divide both sides by .5
(x^2-5x)=-4

Get everything to one side and factor
x^2-5x+4=0
(x-1)(x-4)=0
x-1=0 x-4=0
x=1 x=4

2007-06-03 01:47:57 · answer #1 · answered by math_teacher_02 2 · 0⤊ 0⤋

(xÂ² - 5x)log9 3= -2

(xÂ² - 5x)= -2 / log9 3=-2*log9/log3=-2*2=-4

xÂ² - 5x+4=0
x1=1
x2=4

2007-06-03 08:44:11 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋