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a) explain why we do not normally calculate Ka for hydrochloric acid (HCl)
b) Which acid will have the weaker conjugate base, hypochlorous acid (Ka=3.5x10^-8) or hydrocyanic acid (Ka=4.0x10^-10).
Please explain for each and thank you to the people who are actually helping me.

2007-06-02 23:48:45 · 2 answers · asked by Kimmy 2 in Science & Mathematics Chemistry

2 answers

We normally assume HCl is 100% ionised. Therefore Ka would be infinite!

The weaker the acid, the stronger its conjugate base. Therefore the stronger of the two acids will have the weaker conjugate base: HClO.

2007-06-02 23:56:47 · answer #1 · answered by Gervald F 7 · 0 0

problematic thing. try searching in google. this may help!

2014-11-13 23:08:48 · answer #2 · answered by Anonymous · 0 0

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