solve the equality of x 2x+7<1/3x-4?

Answer 1

uhhhh lol dont ask me ><

Answer 2

Okay so heres what you do. Get the "x's" on the same side. i would suggest subtracting seven to the right and subtracting 1/3 from 2. Make that a mixed number and then multiply by the reciprocal on both sides. then x< than what ever.

2x-1/3x<-4-7
1 2/3x <-11
5/3x< -11
3/5 * 5/3x<-11*3/5
x<-33/5
x<-6.6

Answer 3

sq. the two facets to cancel off the sq. roots: [?(x-3) + ?(2x+a million)] [?(x-3) + ?(2x+a million)] = 3x + 4 strengthen the brackets utilising the foil approach: x - 3 + 2?(x-3)(2x+a million) + 2x + a million = 3x + 4 upload the like words: 3x - 2 + 2?(x-3)(2x+a million) = 3x + 4 Subtract 3x from the two facets: -2 + 2?(x-3)(2x+a million) = 4 upload 2 to the two facets: 2?(x-3)(2x+a million) = 6 Divide the two facets by utilising 2: ?(x-3)(2x+a million) = 3 sq. the two facets to cancel off the sq. root: (x-3)(2x+a million) = 9 strengthen the brackets utilising the foil approach: 2x^2 - 5x - 3 = 9 Subtract 9 from the two facets: 2x^2 - 5x - 12 = 0 factor it out: (2x + 3) (x - 4) = 0 x = 4, - 3/2

Answer 4

To solve inequality eqtns, first treat it as an equality. Then examine the result to re-apply the inequality

2x + 7 = (x/3) - 4
5x/3 = - 11
x = -33/5
No operation was performed that would alter the inequality so x < -33/5

Answer 5

It is asking for whre 2x+7 is less than 1/3x-4.

If you have a graphics calculator, graph both of them. Then simply look for what values of X that 1/3x -4 is greater than 2x+7.

In this case, it is where X is less than -6.6

i.e. x<-6.6.

Answer 6

note
first multiply the equation by 3 to get rid of the fraction

6x + 21 < x - 12
Subtract x from both sides
5x + 21 < - 12
Subtract 21 from both sides
5x < - 33
Divide both sides by 5
x < -33/5

Answer 7

2x+7<1/3x-4
5/3x<-11
5x<-33
x<-33/5 or 6.6