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What mass of solid potassium oxalate (K2C2O4), when dissolved in an acidic solution, would be titrated by exactly 25.0 mL of 0.0177 M potassium permanganate (KMnO4) solution?
(Mn2+ ions and carbon dioxide are produced in the reaction.)


Please show your work and have answer to the correct number of sig. figs. Thanks a lot! =)

2007-06-02 11:54:16 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

MnO4- + 5 e- + 8 H+ -> Mn2+ + 4H2O

C2O4(2-) -> 2 CO2 + 2e-

2 MnO4- + 5 C2O4(2-) + 16 H+ -> 2 Mn2+ 10 CO2 + 8 H2O

Mass of K2C2O4 = 166 * 2.5 * 25 * 0.0177 mg
= 183.6375 mg

2007-06-02 19:41:48 · answer #1 · answered by ag_iitkgp 7 · 0 0

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