during the titration of a 9.00ml aliquot containing chloride ions8.87 mlof 0.0980M Agno3 to end point find M?

Question

find the molarity W/V% concentration and the concentration in ppm of cl-

there is nothign else thhis is how the question is asked so plse help if anyone can !!!!

Answer 1

Moles Ag+ = 0.0980 x 8.87 /1000 = 0.000869 = moles Cl-

[ Cl-] = 0.000869 / 9.0 x10^-3 L = 0.0965 M
ppm = 1 mg / L
0.000869 x 35.453 g/mol = 0.0308 g = 30.8 mg
30.8/9.0x10^-3 =3423 ppm of Cl-

Answer 2

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Answer 3

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