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The position of a particle that moves on a straight line is given by s(t) = t1/t for t > 0.

A)Find the velocity and acceleration

B) At what time, t, is the velocity zero? What is the acceleration at that time?

2007-06-02 10:32:41 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

You differentiate position with respect to "t" to get velocity:

velocity=-t1/t^2 (t>0)


The velocity goes to zero as t goes to infinity.

acceleration = 2*t1/t^3. (i.e. differentiate velocity to get accel)

The acceleration at infinity is also zero.

2007-06-02 10:45:59 · answer #1 · answered by mikeburns55 5 · 0 0

A. v = -2t1/t^2
a=6t1/t^3

B. For v = 0, t approaches infinity for t1 != 0, at that time a = 0

2007-06-02 10:47:35 · answer #2 · answered by QAtlRelo 1 · 0 0

A) Velocity is 1st derivative of position.
Acceleration is 2nd derivative of position (or 1st derivative of velocity).

B) See A, then use algebra.

2007-06-02 10:40:31 · answer #3 · answered by Mr Placid 7 · 0 0

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