Please help
2007-06-02 10:13:20 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
tan(x - π) = [ tanx - tanπ] / (1 - tanx*tanπ)
= tanx / 1
So cot (x - π) = 1/tan(x - π) = 1/tanx = cotx
Alternatively, if you cut the pie in x pieces, how many cuts are there? Answer: x.
2007-06-02 10:18:00 · answer #1 · answered by Dr D 7 · 1⤊ 0⤋
The period of the cot function equals pi;
so it is true.
Cot(alpha + k x pi) = cot(alpha)
for k = ... -2 -1 0 1 2 3 ...
choose k = -1 and you have your case.
Th
2007-06-02 17:21:22 · answer #2 · answered by Thermo 6 · 0⤊ 0⤋
cot (x - Ï)
= (cos x.cos Ï - 0) / (sin x .cos Ï - 0)
= (- cos x) / (- sin x)
= cot x
2007-06-02 18:05:00 · answer #3 · answered by Como 7 · 0⤊ 0⤋
cot(x-pi)
= 1/tan(x-pi)
= cos(x-pi)/sin(x-pi)
= (-cos(x))/(-sin(x)) cancel factors of -1
= cos(x)/sin(x)
= 1/tan(x)
= cot(x)
2007-06-02 17:19:52 · answer #4 · answered by lithiumdeuteride 7 · 0⤊ 0⤋