Decomposition Reaction of Gallium Chlorate?

Question

In the decomposition reaction of gallium chlorate, 75 grams is heated to produce oxygen and gallium chloride.

Calculate the following:
A.) Write the balanced equation for the reaction and find the mole ratios of the reactants and products required to solve any stoichiometric problem.
B.) Find the mass in gram of gallium chloride formed in the reaction.
C.) Find the volume of oxygen in liters formed at 25 Celsius if the gas is collected over mercury under an atmospheric pressure of 670 torr.
D.) How many liters of 2.50 M AgNO3, would be required to titrate all the gallium chloride chloride formed

Answer 1

A) 2 Ga(ClO3)3 -> 2 GaCl3 + 9 O2

Mole ratio = 2:2:9

B
moles Ga(ClO3)3 = 75.0 / 320 = 0.243

the ratio between Ga(ClO3)3 and GaCl3 is 2 : 2 so we would get 0.243 moles GaCl3 (mm = 176.08 g/mol)
0.243 x 176.08 = 42.8 g

C

the ratio between Ga(ClO3)3 and O2 is 2 : 9
2 : 9 = 0.243 : x
x = 1.09 moles O2 produced
V = nRT /p
p = 670 / 760 = 0.881 atm
T = 25 + 273 = 298
V = 1.09 x 0.0821 x 298 / 0.881 = 30.3 L

D
3AgNO3 + GaCl3 >> Ga(NO3)3 + 3 AgCl
the ratio is 3 : 1
3 : 1 = x : 0.243
x = moles AgNO3 = 0.729
M = moles / L
L = moles / M = 0.729 / 2.50 = 0.292 L

Answer 2

A 2Ga(ClO3)3 >>9 O2 +2 GaCl3 2 : 9 :2 B moles Ga(ClO3)3 = 75.0 / 320 = 0.243 the ratio between Ga(ClO3)3 and GaCl3 is 2 : 2 so we wolud get 0.243 moles GaCl3 (mm = 176.08 g/mol) 0.243 x 176.08 = 42.8 g C the ratio between Ga(ClO3)3 and O2 is 2 : 9 2 : 9 = 0.243 : x x = 1.09 moles O2 produced V = nRT /p p = 670 / 760 = 0.881 atm T = 25 + 273 = 298 V = 1.09 x 0.0821 x 298 / 0.881 = 30.3 L D 3AgNO3 + GaCl3 >> Ga(NO3)3 + 3 AgCl the ratio is 3 : 1 3 : 1 = x : 0.243 x = moles AgNO3 = 0.729 M = moles / L L = moles / M = 0.729 / 2.50 = 0.292 L