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A ray of light passes from air into an unknown substance. If the angle of incidence is 54.0 degrees and the angle of refraction is 36.0 degrees, what is the index of refraction of the unknown substance? (The index of refraction of air is 1.00.)

2007-06-02 05:55:43 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

Snell's law is:

sine(angle of incidence 1) * (refractive index 1) =
sine(angle of incidence 2) * (refractive index 2)

or sin54 * 1 = sin36 * r2 where r2 is the refractive index of medium 2.

Or r2 = sin54 / sin36 = 1.376 or let us say 1.38

2007-06-02 06:17:29 · answer #1 · answered by Swamy 7 · 1 0

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2016-05-19 04:27:00 · answer #2 · answered by ? 3 · 0 0

n =sin 54/sin 36 =1.376

2007-06-02 07:14:18 · answer #3 · answered by maussy 7 · 0 0

Snell's law wil let you calculate this

2007-06-02 06:05:53 · answer #4 · answered by Anonymous · 1 0

refractive index=sin(i)/sin(r)
=sin54/sin36
=0.809/0.588
=1.375

2007-06-02 06:03:03 · answer #5 · answered by Anonymous · 0 0

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