(2x-30) (x+60) = 0
<=> x+60 =0 or 2x-30 = 0
<=> x = -60 or x = 15
<=>: equivalent to
2007-06-02 05:43:59
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answer #1
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answered by roman_king1 4
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(2x - 30) (x + 60) = 0
<=>2x - 30 = 0 <=> 2x = 30 <=> x = 15
or x + 60 = 0 <=> x = -60
=>>As a result, I came to the following conclusion:
x = 15 or x = -60
2007-06-02 12:49:41
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answer #2
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answered by â?«Mrs Matthonâ?« 1
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Is it 2x - 30 = x + 60 or is it (2x - 30) (x + 60) = 0 ?
If it is later, 2x - 30 = 0 and or x + 60 = 0 thus giving x = +15 or -60
If 2x - 30 = x + 60, we have 2x - x = 60 + 30 = 90
x = 90
2007-06-02 12:45:11
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answer #3
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answered by Swamy 7
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You can only solve for an unknown, x, if you have an equation.
Assuming that the product given has a result of 0,
(2x-30)(x+60) = 0
2x-30 = 0 and x+60 = 0
2x = 30 and x = -60
x = 15 and -60
2007-06-02 17:03:00
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answer #4
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answered by Kemmy 6
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(2x-30) (x+60)
2x -30 = 0
add 30 to both sides
2x -30 +30 = 0 +30
2x = 30
divide both sides
2x/2=30/2
x=15
Then do the same process for this one
x+60 = 0
x + 60 -60 = 0 -60
x= -60
2007-06-02 12:47:37
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answer #5
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answered by Invisble 4
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"Solve" applies to an equation and this is not an equation.
Multiply the brackets:-
= 2x² + 120x - 30x - 1800
= 2x² + 90x - 1800
= 2.(x² + 45x - 900)
= 2.(x + 60).(x - 15) , upon factorising.
NB
If = 0, x = - 60 , x = 15
2007-06-02 13:26:22
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answer #6
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answered by Como 7
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your given solution is incomplete.....
2007-06-02 12:49:48
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answer #7
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answered by Limarc N 2
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