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The radius of the base of a cone is xcm and the height is h cm.
The radius of the sphere is 2xcm.
the volume of the come and the volume of the sphere are equal.
express H in terms of X.

will someone please tell me step by step how to use algebra in order to solve this?

btw - volume of a sphere is 4/3 pie radius^3
cone is = 1/3 pie radius^2 * height

2007-06-02 05:29:50 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

V_sphere = 4/3 * π * (2x)^3 = 32πx^3/3

V_cone = 1/3 * H * π x^2 = π HX^2 / 3

So HX^2 = 32X^3
H = 32X

2007-06-02 05:34:46 · answer #1 · answered by Dr D 7 · 1 0

Volume of cone = Volume of sphere
(1/3)(pi)(x^2)(h) = (4/3)(pi)(2x)^3

Cancel away the (1/3) and pi on both sides:
(x^2)(h) = 4(8x^3)
h = 4(8x^3)/(x^2)
h = 32x

2007-06-02 10:08:03 · answer #2 · answered by Kemmy 6 · 0 0

V sphere = (4/3).π.(2x)³ = (1/3).32.π.x³
V cone = (1/3).π.x².h
x².h = 32.x³
h = 32.x

2007-06-02 06:42:12 · answer #3 · answered by Como 7 · 0 0

1/3*pi*x^2*h=4/3*pi*(2*x)^3
1/3*x^2*h=4/3*(2*x)^3
x^2*h=4*(2*x)^3
x^2*h=4*8*x^3
h=32*x

2007-06-02 05:35:25 · answer #4 · answered by Anonymous · 0 0

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