Given f(x) = 5x^2 -3x + 1, find f(-2)
2007-06-02 05:22:07 · 8 answers · asked by davidu69 1 in Science & Mathematics ➔ Mathematics
f(-2) = 5(-2)^2 - 3(-2) + 1 = 27
2007-06-02 05:25:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
f(-2)= 5.(-2).(-2) - 3.(-2) +1
= 20 + 6 +1
= 27
2007-06-02 05:43:38 · answer #2 · answered by â?«Mrs Matthonâ?« 1 · 0⤊ 0⤋
f(-2) = 5 X 4 + 6 + 1 = 27 (x^2 will be +ve and -3x will also be +ve).
2007-06-02 05:25:39 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
Just plug in -2 for x. 5(-2)^2 - 3(-2) + 1
2007-06-02 05:27:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5^x2 - 3x + 1= f(x)
now we just substitute 2 with x
so, f(-2) = 5 x (-2)^2 - 3 x (-2) + 1
f(-2) = 27
2007-06-02 05:43:43 · answer #5 · answered by zaheen797 3 · 0⤊ 0⤋
f(-2)=5(4)-3(-2)+1
20+6+1
=27
2007-06-02 05:26:13 · answer #6 · answered by Anonymous · 0⤊ 0⤋
f(-2) = 5 x 4 + 6 + 1
f(-2) = 27
2007-06-02 06:22:59 · answer #7 · answered by Como 7 · 0⤊ 0⤋
only replace the -2 for the x's: 5(-2)(-2) - 3(-2) + a million Now multiply and beware for the damaging indicators. Your answer would be effective once you multiply 2 negatives.
2016-11-25 00:59:34 · answer #8 · answered by pao 4 · 0⤊ 0⤋