Perhaps the question is (7x-40)(4x-5)=0
Therefore, either 7x-40=0----> x=40/7
or 4x-5=0----->x=5/4
x=5/4, 40/7
x=1 1/4, 5 5/7
2007-06-02 05:09:51
·
answer #1
·
answered by Jain 4
·
0⤊
0⤋
(7x-40)(4x-5)=0
Therefore either (7x – 40) = 0 or (4x – 5) = 0
Therefore ----> 7 x = 40 or 4 x = 5
Therefore x = 40/7 or x = 5/4
x = 5/4, 40/7
2007-06-05 02:43:17
·
answer #2
·
answered by Pranil 7
·
0⤊
0⤋
from the first parenthetical expression,
7x = 40
so
x = 40/7
and from the second,
4x = 5
so
x = 5/4
2007-06-02 12:10:17
·
answer #3
·
answered by Mark S, JPAA 7
·
0⤊
0⤋
if (7x-40)(4x-5)=0
either 7x-40=0----> x=40/7
or 4x-5=0----->x=5/4
x=5/4, 40/7
2007-06-04 02:18:39
·
answer #4
·
answered by Sumita T 3
·
0⤊
0⤋
7x-40=0
4x-5=0
7x-40+40=0+40
7x=40
x=40/7= 5 5/7
4x-5=0
4x-5+5=0+5
4x=5
x=5/4=1 1/4
2007-06-02 12:25:46
·
answer #5
·
answered by Dave aka Spider Monkey 7
·
0⤊
0⤋
(7x-40)(4x-5)=0
x=40/7,5/4 answer
2007-06-02 12:22:34
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋