A volleyball is spiked so that it has an initial velocity of 15 m/s directed downward at an angle of 61° below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?
Please show your work, having trouble figuring out how you can find the lengths of the triangle.
2007-06-02 02:34:12 · 3 answers · asked by wildcherrychica1 2 in Science & Mathematics ➔ Physics
If it's spiked down at an angle of 61°, then the x and y (horizontal and vertical) components of the velocity vector are given by
x = 15 cos(61) = 7.27 m/s and
y = 15 sin(61) = 13.12 m/s
(Hint: When in doubt, draw a picture ☺)
Doug
2007-06-02 02:56:45 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
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2016-10-09 07:37:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
:-D Doug...
They don't teach graph paper techniques anymore.
2007-06-02 03:38:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋