I need help with math homework please. I'm not good with radical equations. Explain me how you get the answer.

Question

1.) The square root of 5x= 20
2.) The sqrt of (x) -7=-3
3.) 6- sqrt of (2x)= -2
4.) The sqrt of (2x-1)=5
5.) 10= sqrt of (6x+2) +5
6.) The sqrt of (3x+13)= sqrt of (20-4x)

Please explain me how you get the answer so I understand.

Answer 1

sqrt of 5x=20
(sqrt of 5x=20)^2= 5x=400 x= 80

sqrt of x-7=-3
(sqrt of x)-7=-3)

(sqrt of x)-7+7=-3+7
(sqrt of x)=4
sqrt of x^2=4^2
x=16

6-sqrt of 2x=-2
-sqrt of 2x=-8
-sqrt of2x)^2=-8^2
2x=64
x=32

(sqrt of 2x-1)=5
(sqrtof 2x-1)^2=5^2
2x-1=25
2x-1+1=25+1
2x=26
x=13

10=( sqrt of 6x+2)+5
10-5=(sqrt of 6x+2)+5-5
5=(sqrt of 6x+2)
5^2=(sqrt of 6x+2)^2
25=6x+2
25-2=6x+2-2
23=6x
23/6=6x/6
23/6=3 5/6 = x

sqrt of 3x+13=sqrt of 20-4x
(sqrt of 3x+13= sqrt of 20-4x)^2
3x+13=20-4x
3x+4x+13=20-4x+4x
7x+13-13=20-13
7x=7
x=1

Answer 2

1. x = 80
2. x = 16
3. x = 32
4. x = 13
5. x = 3 5/6 or 3.833
6. x = 1

Answer 3

1) sqrt(5x) = 20.
So square both sides to "eliminate" the radical

5x = 20^2
5x = 400
x = 80

etc.

Answer 4

solve for x and then find the square root of that number