Find the slope of the line passing through the points (–9, –1) and (–2, –1).?

Answer 1

slope = gradient(m)
there is 2 formula to find m,
1. y = mx + c
2. (Y2 - Y1) / (X2 -X1)
here we use the 2nd formula.

Y1= -1
Y2= -1

X1= -9
X2= -2

now we just put the values in the formula,
(-1 - -1) / (-2 - -9) = m
0 = m

Answer 2

We are asked to find the slope of the line that passing through the points (-9,-1) and (-2,-1).
The formula is given by,

m = (y2-y1)/ (x2-x1)
where m represents the slope of the line.
Let's take (x1,y1) = (-9,-1) and (x2,y2) = (-2,-1)
Plug the values and get,

m = (-1+1)/(-2+9)
= 0
That is we get the slope m =0.

** note: x1,y1,x2 and y2 are supposed to be x subscript 1 and so on.

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Answer 3

Gradient= rise/tread
Rise= -1--1=0
Tread=-9--2=-7

Gradient= 0/-7 =0
The gradient is 0. ie a horizontal line.

Answer 4

m = Y2-Y1
_____
X2-X1
= (-1)-(-1)
______
(-2)-(-9)
= -1+1
___
-2+9

m = 0/7
.: it is a horizontal slope.

Hope I'm right :)

Answer 5

Easy, it's 0.
Now --you-- need to get busy and find out why ☺

Doug