what would the prime factorization be for 122 and what would the GCF (greatest common factor) be for 108 and 24
2007-06-02 02:09:48 · 6 answers · asked by xodanceox 2 in Science & Mathematics ➔ Mathematics
122
/ \
2 61
108 24
Both have a 2,
54, 12
Both have a 2,
27, 6
Both have a 3
9, 2
2*2*3 = 12.
2007-06-02 02:18:10 · answer #1 · answered by Nick C 3 · 0⤊ 0⤋
prime factorization:
122
/ \
2 61
I think 61 is prime.
The prime factorization would be 2*61 because they are the prime numbers that you can multipy together to get 122.
GCF:
108: 1, 2, 3, 4, 6, 9, ~12~, 18, 27, 36, 54
24: 1, 2, 3, 4, 6, 8, ~12~
In this case the GCF is 12 because it is the largest number that is common in both sets of numbers. The LCM is the least common multiple, which is the smallest multiple.
Here are some definitions:
Prime Factorization: the process of decomposing a number into its constituent prime numbers; the calculation of all prime factors in a number
Greastest Common Factor: the largest integer that divides without remainder into a set of integers
Least Common Multiple: The smallest quantity that is divisible by two or more given quantities without a remainder
If you ever need any more math help, just mail me at wild.child.rocka@gmail.com!
Hope this helps!
2007-06-02 02:30:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Prime Factorization of 122 would be 2*61
GCF of 108 and 24 is 12
2007-06-02 02:16:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋
122 = 2*61 since 61 is a prime that is as far as you can go.
108 = 2*54 = 2*2*27 = 2*2*3*9 = 2*2*3*3*3 since all are primes that is as far as you can go
24 = 2*12 = 2*2*6 = 2*2*2*3 since all are primes that is as far as you can go
GCF(108,24) = 2*2*3 = 12 since each of these factors appear in both numbers
2007-06-02 02:20:08 · answer #4 · answered by cscokid77 3 · 0⤊ 0⤋
A prime factorization is a way of writing a number as a product of primes: a^n * b^m * c^k and so on where a, b, and c are prime numbers, and n, m, and k are the number of times that that number is a factor of our original number. But now suppose that n, m, and k are all zero, so that we have: a^0 * b^0 * c^0 = 1 * 1 * 1 = 1. Another idea to ponder is that "doing nothing" in terms of multiplication is NOT 0. It's 1. So "No prime factors" means that the greatest common factor is 1. Notice that 1 is a factor of every integer. Finally - YES it is TECHNICALLY impossible. But can you find a number which does not have 1 as a factor? Can you find two numbers which don't have 1 as a common factor?
2016-05-19 02:55:44 · answer #5 · answered by ? 3 · 0⤊ 0⤋
122-2
61-61
1
122=2*61
108-24-2*
54-12-2*
27-6-2
27-3-3*
9-1-3
3-1-3
1-1
GCF=2*2*3=12
2007-06-02 02:17:09 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋