"Tropical shrimp trawling has the highest bycatch of any commercial fishery: 3 to 15 pounds of unwanted animals are caught and discarded per pound of shrimp landed."
So let's use the average of 3 and 15, which is 9. If the ratio of bycatch to shrimp is 9:1 then
(A) How many pounds of marine life must be caught in total to get 2 pounds of shrimp?
(B) How would you express the amount of shrimp out of the total amount of marine life as a fraction?
2007-06-01 21:52:19 · 5 answers · asked by AdvisenEthics 2 in Education & Reference ➔ Homework Help
b = 1/9
THEREFORE
a ) 1/9 = 2/ X
solve for x
still stumped?
mutiply 1/9 times 2/2
2 x 1 = 2
2 x 9 =
2007-06-01 21:56:57 · answer #1 · answered by tom4bucs 7 · 0⤊ 0⤋
a) If the ratio is 9:1, then 18:2. So the answer is 20, because 18 pounds of bycatch and 2 pounds of shrimp must be caught, making the total 20.
b) Since the ratio is 9:1, the fraction is 1/10, because shrimp is included in the total as well.
2007-06-01 22:30:17 · answer #2 · answered by Su Gi C 2 · 0⤊ 0⤋
A) 18 pounds of marine life for 2 pounds of shrimp
B) 1/10 as a fraction... since the total marine life would include the shrimp as well
2007-06-01 22:05:08 · answer #3 · answered by Sean H 2 · 0⤊ 0⤋
(A)9*2:1*2
18:2
18
(B)1/(9+1)
1/10
2007-06-01 22:02:16 · answer #4 · answered by Rale Baskinson 3 · 0⤊ 0⤋
next time go to the "mathematics" section it is better.
can i have 10 pts please :)
2007-06-01 21:59:15 · answer #5 · answered by Robin 4 · 0⤊ 1⤋