Is this a true or false statement and why?
Thanks for any help you can give me :)
2007-06-01 17:05:45 · 15 answers · asked by kat123 1 in Science & Mathematics ➔ Mathematics
SQRT(16x^16)
= SQRT16 * SQRTx^16
= 4x^8
2007-06-01 17:10:45 · answer #1 · answered by Kemmy 6 · 0⤊ 1⤋
No, the statement is false.
sqrt(16 * x^16) = sqrt(16) * sqrt(x^16)
= + or - 4 * (x^16)^(1/2)
= + or - 4 * [x^(16/2)]
= + or - 4x^8.
Hope u found this useful...........
2007-06-02 00:57:20 · answer #2 · answered by Hellboy 1 · 0⤊ 0⤋
No, To make this simpler to see, you can change the square root into a (1/2) power. So you have:
(16^16)^(1/2)
When you have a power raised to a second power you sijmply multiply the two powers...
therefore:
16^8 will be your final answer.
2007-06-02 16:33:59 · answer #3 · answered by Joseph P 4 · 0⤊ 0⤋
sqrt(16x^16)=4x^4
i.e. 4x^8 = 4x^4
i.e. x^8 = x^4 if it is true,
Then x = 1 or x = 0
2007-06-03 04:08:20 · answer #4 · answered by Pranil 7 · 0⤊ 0⤋
You should first split that as sqrt(16)Xsqrt(x^16) to avoid any confusions.
You will now get 4x^8.
That's the answer. Simple!
2007-06-02 05:31:42 · answer #5 · answered by Nivvedan 2 · 0⤊ 0⤋
its false as sqr.root of 16x^16 is 4x^8 as x^16/2=x^8
2007-06-03 06:05:34 · answer #6 · answered by Anonymous · 0⤊ 0⤋
no
sqrt(16x^16) = sqrt(16) sqrt(x^16) = 4x^8
2007-06-02 00:10:25 · answer #7 · answered by 7 · 0⤊ 1⤋
no,
(16 x^16) is not equal to (4x^4).
we know,
16=2x2x2x2 ,
4=2x2,
therefore, 16x^16= ( 2x^4)x^16 = (2x^64),
so, sqrt. (16x^16)=(2x^32),
and, 4x^4=(2x^2)x^4=2x^8,
as,
(2x^32) not equal to (2x^8)
or, sqrt.(16x^16) not equal to (4x^4)
2007-06-02 00:39:03 · answer #8 · answered by Indranil M 2 · 0⤊ 0⤋
(4 *X^4)^2= 4^2*(x^4)^2= 16*X^8
The actual answer is sqrt(16x^16) =+/-4*X^8
2007-06-02 00:45:49 · answer #9 · answered by A.V.R. 7 · 0⤊ 0⤋
sqrt(16)*sqrt(x^16)
sqrt(16)= +/-4
sqrt(x^16)=sqrt(x^8)^2
sqrt & power 2 gets canceled so
sqrt(x^16)= +/-x^8
ANS : : +/- 4x^8
2007-06-02 01:22:12 · answer #10 · answered by yogitap 2 · 0⤊ 0⤋