Calculate volume of Carbon Dioxide?

Question

Gasoline is a blend of hydrogen and oxygen. Calculate the volume of carbon dioxide, at 300 Degrees C and 110 KPa, that will pass through the muffler of a car during combustion of a full tank (50.0 kg) of gasoline. Assume the chemical formula of gasoline is C7H16.
Balance chemical equation is: C7H16 + 11 O ==> 7 CO2 + 8 H2O
Then I know I have to convert temperature to Kelvins : 300 + 273 = 573k
Then convert given mass to moles 50.0 * 10^3 g * 1 mol / 44.0 g CO2 = 1.136 mol
Then 1.136 * (and now I am lost) Any help would be appreciated.

Answer 1

I think this is how you do it: I assume no legal resposnibility if you get an "F" on your homework! This program doesn't lend its self well to complex math equations I hope you can follow it.

Determine moles of gasoline (octane)

[50kg x 1000g/kg]/100g per mole octane = 500 moles

From the balanced equtation determine no of moles of CO2 that would be made

500 x 7 = 3500moles CO2

Convert 110kpa to Atm [look up conversion factor(s)]
Note convesion to lb/in2, then atm! I couldn't find direct conversion.

[110Kpa x 0.145lb/in2perKpa]/14.7 lb/in2/atm = 1.085 atm

Now use the ideal gas law to get volume in liters:

PV = nRT Make certain to use the right gas constant (R)! and T in kelvin!

1.085atm x [volume] = 3500 mol x 0.08205latm/K,mol x 573 K

Solve for volume:

volume = [3500 x 0.08205 x 573]/1.085

V = 151,600 liters

Your question did not specify what volume units; I did it in liters which is fairly common, if you need it in other units you can convert at your leisure. I hope this is correct, I haven't done this in a while.

Answer 2

a million mole CaCO3 --> a million mole CO2 Ar values: Ca = 40 C = 12 O = sixteen (x 3 as there are 3 oxygen atoms) So finished Mr for CaCO3 = 40 + 12 + (16x3) = 100g Ar values: C = 12 O = sixteen (x 2 as there are 2 oxygen atoms) So finished Mr for CO2 = 12 + (sixteen x 2) = 44g then do a million.2/a hundred = 0.012 40 4 x 0.012 = 0.528g CO2 that's how plenty CO2 you get in grams from a million.2 g of calcium carbonate, yet i'm undecided the way you exchange that right into a quantity!!

Answer 3

Mr of C7H16 is (very helpfully) 100 exactly.

Moles C7H16 = 50,000/100 = 500.

Now multiply by 7 to the get the moles of CO2 = 7 x 500 = 3,500 (this is n for CO2).

Now use V = nRT/p to calculate the volume of CO2.

Over to you!