in 1mL of 10^-4 M (mol/L) H2SO4 solution there are:
1,2*10^17 H^+ ions
This is the correct answer. I didn't got that
2007-06-01 05:14:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
moles of H2SO4 = 0.001L x 10^-4 M = 10^-7 mol
H2SO4-->2H+ + SO42-
moles of H+ = 2 x10^-7 mol
1 mol H+ ions = 6.02 x 10^23 H+ ions
2 x10^-7 mol H+ ions = 6.02 x10^23 x 2 x 10^-7
= 12.04 x 10^16 ions
= 1.20 x 10^17 ions
does it make sense?
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2007-06-01 05:23:50 · answer #1 · answered by Anonymous · 0⤊ 0⤋
In 1 mL 10 -4 M = 2 x 10 -7 Moles H ions
6,02 x 10 23 x 2 x 10 -7 = 1.2 x 10 17
2007-06-01 12:24:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1 litre of 10^-4 M solution of H2SO4 would have
1*10^-4*N*2
Where 1 - 1 litre
10^-4 - Concentration in Molarity
N - Avogadro number
2 - Because there are 2 H+ ions
When you consider 1mL, there would be 10^-3 this number of ions (i.e one thousandth of that answer)
so the final answer is 10^-4 x 10^-3 x 2 x 6.022x10^23
which is : 12.044 x 10^16 = 1.2x10^17....so you are right! :)
2007-06-01 12:22:44 · answer #3 · answered by Ohil 3 · 0⤊ 0⤋
avagdro hypothesis
one mole of any substance contains 6.023*10^23 particles
therefore 10^-4 mole of sulfuric acid contains 6.023*10^19 sulfuric acid molecule.
one molecule of sulfuric acid dissociates to give 2 proton
hence 10^-4 mole of it contains 1.2046 *10^20 protons
1ml of 10^-4 sulfuric acid contains 1.2046*10^20*10^-3
which is = 1.2046810^17 protons
2007-06-01 12:28:23 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Yes thats the correct one.
2007-06-01 12:51:49 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋